Question 25

In ΔDEF measure of angle E is 90o. If cot D = $$\frac{5}{12}$$, and DE = 1cm, then what is the length (in cm) of side EF?

Solution

Given : DE = 1 cm and cot D = $$\frac{5}{12}$$

To find : EF = ?

Solution : In right $$\triangle$$ DEF,

=> $$cot(D)=\frac{DE}{EF}$$

=> $$\frac{5}{12}=\frac{1}{EF}$$

=> $$EF=\frac{12}{5}\times1=2.4$$ cm

=> Ans - (A)

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