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If 7-digit number 78*3945 is divisible by 11, then value of '*' is
For divisibility by 11, the difference between the sums of digits in odd and even places (from the right) must be a multiple of 11. The odd-place digits are 5, 9, *, 7 with sum $$21 + \ast$$ and the even-place digits are 4, 3, 8 with sum 15. So $$6 + \ast$$ must be 11, giving $$\ast = 5$$.
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