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For each positive integer $$n$$ let $$f(n)=n^4-3n^2+9$$. Then the sum of all $$f(n)$$ which are prime is
Correct Answer: 20
Factor the expression as $$f(n)=(n^2+3n+3)(n^2-3n+3)$$. For the product to be prime, the second factor must equal $$1$$, which occurs for $$n=1$$ and $$n=2$$. These give $$f(1)=7$$ and $$f(2)=13$$, so the required sum is $$20$$.
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