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Given : $$\cot D$$ = $$\frac{5}{12}$$
Also, $$\cot D=\frac{DE}{EF}=\frac{5}{12}$$
Let DE = 5 cm and EF = 12 cm
Thus, in $$\triangle$$ DEF, => $$(DF)^2=(DE)^2+(EF)^2$$
=> $$(DF)^2=(5)^2+(12)^2$$
=> $$(DF)^2=25+144=169$$
=> $$DF=\sqrt{169}=13$$ cm
To find : $$\sin F=\frac{DE}{DF}$$
= $$\frac{5}{13}$$
=> Ans - (C)
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