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Question 25
ΔABC is right angled at B. If $$cot A = \frac{7}{24}$$, then what is the value of $$cosec C$$ ?
Solution
Given : $$\cot A$$ = $$\frac{7}{24}$$
Also, $$\cot A=\frac{AB}{BC}=\frac{7}{24}$$
Let AB = 7 cm and BC = 24 cm
Thus, in $$\triangle$$ ABC,
=> $$(AC)^2=(AB)^2+(BC)^2$$
=> $$(AC)^2=(7)^2+(24)^2$$
=> $$(AC)^2=49+576=625$$
=> $$AC=\sqrt{625}=25$$ cm
To find : $$\cosec C=\frac{AC}{AB}$$
= $$\frac{25}{7}$$
=> Ans - (B)
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