Question 25

ΔABC is right angled at B. If $$cot A = \frac{7}{24}$$, then what is the value of $$cosec C$$ ?

Solution

Given : $$\cot A$$ = $$\frac{7}{24}$$

Also, $$\cot A=\frac{AB}{BC}=\frac{7}{24}$$

Let AB = 7 cm and BC = 24 cm

Thus, in $$\triangle$$ ABC,

=> $$(AC)^2=(AB)^2+(BC)^2$$

=> $$(AC)^2=(7)^2+(24)^2$$

=> $$(AC)^2=49+576=625$$

=> $$AC=\sqrt{625}=25$$ cm

To find : $$\cosec C=\frac{AC}{AB}$$

= $$\frac{25}{7}$$

=> Ans - (B)


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