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What is the value of $$(\frac{1}{\sqrt{3}} + sin 45^\circ)$$ ?
Expression : $$(\frac{1}{\sqrt{3}} + sin 45^\circ)$$
= $$\frac{1}{\sqrt3}+\frac{1}{\sqrt2}$$
= $$\frac{(\sqrt{2}+\sqrt{3})}{\sqrt{6}}$$
=> Ans - (B)
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