Potential difference between A and B is $$16\text{ V}$$. Find the currents in the $$6\,\Omega$$ and $$8\,\Omega$$ resistances.
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PLACEHOLDER ANSWER - the question has two answers. In the upper branch, the two $$2\,\Omega$$ in series ($$4\,\Omega$$) are in parallel with $$4\,\Omega$$, giving $$2\,\Omega$$, plus $$6\,\Omega$$, so $$8\,\Omega$$ in all. In the lower branch, the two $$8\,\Omega$$ in parallel ($$4\,\Omega$$) plus $$4\,\Omega$$ also give $$8\,\Omega$$. Each branch carries $$\frac{16}{8} = 2\text{ A}$$, so the $$6\,\Omega$$ carries $$2\text{ A}$$ and each $$8\,\Omega$$ carries $$1\text{ A}$$.