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Consider an electrical circuit containing a two way switch $$S$$. Initially $$S$$ is open and then $$T_1$$ is connected to $$T_2$$. As the current in $$R = 6 \, \Omega$$ attains a maximum value of steady-state level, $$T_1$$ is disconnected from $$T_2$$ and immediately connected to $$T_3$$. Potential drop across $$r = 3 \, \Omega$$ resistor immediately after $$T_1$$ is connected to $$T_3$$ is _________ V. (Round off to the Nearest Integer)
Correct Answer: 3
We need to find the potential drop across the resistor $$r = 3\ \Omega$$ immediately after the switch $$S$$ is flipped from terminal $$T_2$$ to terminal $$T_3$$.
Initially, terminal $$T_1$$ is connected to $$T_2$$ for a long time until the circuit reaches a steady state:
Using Ohm's Law, we calculate the maximum steady-state current ($$I_0$$) flowing through the inductor:
$$I_0 = \frac{V}{R} = \frac{6\text{ V}}{6\ \Omega} = 1\text{ A}$$
At $$t = 0$$, terminal $$T_1$$ is disconnected from $$T_2$$ and instantly connected to $$T_3$$:
$$I(0^+) = I_0 = 1\text{ A}$$
Now, we can find the instantaneous potential drop ($$V_r$$) across the resistor $$r = 3\ \Omega$$ using Ohm's Law:
$$V_r = I(0^+) \times r$$
$$V_r = 1\text{ A} \times 3\ \Omega = 3\text{ V}$$
The potential drop across the $$r = 3\ \Omega$$ resistor immediately after the connection change is 3 V.
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