Solution
$$2\sec^2 x - \tan^2 x = 5$$
$$\sec^2x+\sec^2x-\tan^2x=5$$
$$1+\sec^2x=5$$ ($$\sec^2x-\tan^2x=1$$)
$$\sec^2x=4$$
$$^{\sec^260^{\circ\ }=4\ \left(\sec60^{\circ\ }=2\right)}$$
Get AI Help
Create a FREE account and get:
- Download RRB Study Material PDF
- 45+ RRB previous papers with solutions PDF
- 300+ Online RRB Tests for Free
