Which two signs should be interchanged in the following equation to make it correct?
$$9-3+12\times8\div4=11$$

By Trial and Error method,

Option A

$$9+3-12\times8\div4=11$$

$$9+3-12\times2=11$$

$$9+3-24=11$$

$$-12=11$$

Hence option A is incorrect

Option B

$$9-3\times12+8\div4=11$$

$$9-3\times12+2=11$$

$$9-36+2=11$$

$$-25=11$$

Hence option B is incorrect

Option C

$$9\div3+12\times8-4=11$$

$$3+12\times8-4=11$$

$$3+96-4=11$$

$$95=11$$

Option D

$$9-3\div12\times8+4=11$$

$$9-\frac{1}{4}\times8+4=11$$

$$9-2+4=11$$

$$11=11$$

Hence, the correct answer is Option A