Question 22

Travelling at 3/4 of the normal speed, a person reaches his workplace 15 minutes late. How many minutes does he take usually to reach the workplace?

Solution

let s be his normal speed
t = his normal time

as we know that 

D = $$s\times t$$

then
$$D = (\frac{3}{4})s\times  (t+15)$$
here the distance is the same we can equate this to his regular day which is D = $$s\times t$$
$$s\times t = (\frac{3}{4})s\times (t+15)$$

t=45 minutes


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