In the given figure, $$ABCD$$ is a rectangle. The measure of angle $$x$$ is _______________ degrees.

Let us mark the points as shown in the figure as $$E$$ , $$G$$ and $$F$$

Now, line $$AB$$ is parallel to $$CD$$

So, $$\angle BEF+162=180$$°

$$\angle BEF=18$$°

And, $$\angle EFG=28$$°

Now, in triangle $$BEF$$

$$\angle EBF+\angle BFE+\angle FEB=180$$°

$$90+\angle BFE+18=180$$°

$$\angle BFE=72$$°

Now, Since lines $$AB$$ and $$BC$$ are parallel

So, $$x=\angle BFG$$

or, $$x=\angle BFE+\angle EFG$$

or, $$x=72+28=100$$°