Question 22

If $$\frac{x}{\sqrt{128}}$$=$$\frac{\sqrt{162}}{x}$$ then find the value of x

Solution

$$\frac{x}{\sqrt{128}}=\frac{\sqrt{162}}{x}.$$

or,$$x^2=\sqrt{162}\times\sqrt{128\ }.$$

or,$$x^2=\sqrt{9^2\times2}\times\sqrt{8^2\times2\ }.$$

or,$$x^2=9\times2\times8=144.$$

or,$$x=12.$$

A is correct choice.

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