Solution
$$\frac{x}{\sqrt{128}}=\frac{\sqrt{162}}{x}.$$
or,$$x^2=\sqrt{162}\times\sqrt{128\ }.$$
or,$$x^2=\sqrt{9^2\times2}\times\sqrt{8^2\times2\ }.$$
or,$$x^2=9\times2\times8=144.$$
or,$$x=12.$$
A is correct choice.
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