Question 22
Given that $$10^{0.48} = x, 10^{0.70} = y$$ and $$x^{z} = y^{2}$$, then the value of z is close to:
Solution
Given, $$10^{0.48} = x, 10^{0.70} = y$$ and $$x^{z} = y^{2}$$
$$(10^{0.48})^z = 10^{0.70}^2$$
$$10^{0.48*z} = 10^{0.70*2} = 10^{1.4}$$
0.48*z=1.4
$$\Rightarrow z = \frac{1.4}{0.48} = 2.91$$
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