Sign in
Please select an account to continue using cracku.in
↓ →
In how many ways can 7 different balls be distributed in 5 different boxes. If any box can contain any number of balls except that ball 3 can only be put into box 3 or box 4 ?
Let's number the balls as 1, 2, 3, 4, 5, 6, 7.
We have a condition on ball 3; it can be placed in either box 3 or 4. So, ball 3 has two chances.
All the remaining balls can be placed in any of the five boxes. This can be done in 5*5*5*5*5*5=$$5^6$$
The total number of ways is $$2*5^6$$.
Create a FREE account and get:
Enroll in Cracku's CUET PG 2026 coaching now
Educational materials for CAT preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.