Using 3 identical wires each having resistance $$30\,\Omega$$, letter 'B' is formed. Ends of the straight wire are connected to a cell of potential difference $$220\text{ V}$$. (i) Find the effective resistance of the circuit (ii) find the rate at which energy is delivered by the cell?

PLACEHOLDER ANSWER - the question has two answers. The straight wire is split by the middle junction into two halves of $$15\,\Omega$$, and each curved wire of $$30\,\Omega$$ is in parallel with one half, giving $$\frac{15 \times 30}{45} = 10\,\Omega$$. The two halves are in series, so the effective resistance is $$20\,\Omega$$. The power delivered is $$\frac{220^2}{20} = 2420\text{ W}$$.