$$P^{3-}$$ has a larger radius than atom of $$P$$ because

A

There is greater coulombic attraction between the nucleus and electrons in the $$P^{3-}$$ ion.

B

The core electrons in $$P^{3-}$$ exert a weaker shielding force than those of a neutral atom.

C

The nuclear charge is weaker in $$P^{3-}$$ than it is in $$P$$.

D

The electrons in $$P^{3-}$$ have a greater coulombic repulsion than those in $$P$$ atom.