RRB JE 28th May 2019 Shift-3

Question 21

If $$1.5x = 0.04y$$, find the value of $$\frac{(y - x)}{(y + x)}$$.

Solution

$$1.5x = 0.04y$$

$$\frac{x}{y}$$ = $$\frac{0.04}{1.5}$$

$$\frac{(y - x)}{(y + x)}$$ =$$\frac{(1.5-0.04)}{(1.5+0.04)}$$

                                     =$$\frac{(1.46)}{(1.54)}$$

                                     =$$\frac{(73)}{(77)}$$

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