How many moles of the so-called electron gas weighs one kilogram?

A

$$\frac{6.02}{9.11}\times10^{54}$$

B

$$\frac{100}{6.02\times9.11}\times10^6$$

C

$$6.02\times10^{23}$$

D

$$\frac{10}{9.11}\times10^{30}$$