In the following logic circuit the sequence of the inputs $$A$$, $$B$$ are $$(0, 0), (0, 1), (1, 0)$$ and $$(1, 1)$$. The output $$Y$$ for this sequence will be:

1. Identify the Logic Gates

Let's analyze the configuration of the gates in the circuit layout:

• The first gate is a NAND gate with two inputs, $$A$$ and $$B$$. Its output expression is:

  $$Y_1 = \overline{A \cdot B}$$

• The output $$Y_1$$ is split and fed directly into both inputs of a second NAND gate, which causes it to function as a NOT gate.
• Therefore, the final output $$Y$$ is simply the inversion of $$Y_1$$:

  $$Y = \overline{Y_1} = \overline{\overline{A \cdot B}} = A \cdot B$$

Thus, the overall logic circuit simplifies to a basic AND gate function.

2. Evaluate the Input Sequence

Now, let's substitute the given input combinations for $$(A, B)$$ into the AND logic expression ($$Y = A \cdot B$$):

3. Match with the Options

The resulting output sequence for the combinations $$(0,0), (0,1), (1,0), (1,1)$$ is 0, 0, 0, 1.

Correct Option: B (0, 0, 0, 1)