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Choose the correct waveform that can represent the voltage across $$R$$ of the following circuit, assuming the diode is ideal one:
When the input signal rises above the reference battery voltage ($$+3\text{ V}$$), the diode becomes forward-biased and acts as a short circuit (closed switch).
Applying Kirchhoff's Voltage Law (KVL) around the conducting loop:
$$v_i - V_R - 3 = 0 \implies V_R = v_i - 3$$
$$V_R = 10 - 3 = +7\text{ V}$$
When the input voltage drops below or equals the reference battery level ($$\le +3\text{ V}$$), the diode is reverse-biased and acts as an open circuit (open switch).
$$V_R = 0\text{ V}$$
The resulting voltage waveform across the load resistor ($$V_R$$) must satisfy two visual rules:
This exact profile—clipping flat at $$0\text{ V}$$ and tracking only the upper peak relative to the shifted reference axis—corresponds to the first choice on the page layout.
Correct Option: A
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