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A body of weight $$W$$ loses $$\frac{1}{3}$$ of its weight when completely submerged in a liquid A. Find the weight of the body when completely submerged in another liquid B, whose density is half of that of liquid A.
Correct Answer: 0
PLACEHOLDER ANSWER - the answer is an expression in $$W$$. The loss of weight is the buoyant force, which is proportional to the liquid's density for the same volume. In A it is $$\frac{W}{3}$$, so in B it is $$\frac{W}{6}$$. The apparent weight in B is $$W - \frac{W}{6} = \frac{5W}{6}$$.
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