Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
Torque:
Torque is given by force × distance.
$$\tau=r\times F$$
Dimensions of force:
$$[F]=[MLT^{-2}]$$
So,
$$[\tau]=[L]\cdot[MLT^{-2}]=[ML^2T^{-2}]$$
So, Torque → (IV)
Magnetic field:
From Lorentz force,
$$F=qvB$$
$$B=\frac{F}{qv}$$
Now substitute dimensions:
$$[q]=[AT]$$
$$\quad[v]=[LT^{-1}]$$
$$[B]=\frac{MLT^{-2}}{(AT)(LT^{-1})}=[MT^{-2}A^{-1}]$$
So, Magnetic field → (III)
Magnetic moment:
Magnetic moment is given by:
$$μ=IA$$
$$[\mu]=[A]\cdot[L^2]=[L^2A]$$
So, Magnetic moment → (II)
Permeability of free space:
Using relation:
$$B=\mu_0\frac{I}{L}$$
$$\mu_0=\frac{BL}{I}$$
Substitute dimensions:
$$[B]=[MT^{-2}A^{-1}]$$
$$[\mu_0]=\frac{(MT^{-2}A^{-1})\cdot L}{A}=[MLT^{-2}A^{-2}]$$
So, Permeability → (I)
Final matching:
(A)−(IV), (B)−(III), (C)−(II), (D)−(I)
Create a FREE account and get:
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.