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Consider a triangle ๐๐๐ having sides of lengths ๐, ๐ and ๐ opposite to the angles ๐,๐ and ๐ , respectively. Then which of the following statements is (are) TRUE ?
$$\cos P \geq 1 - \frac{p^{2}}{2qr}$$
$$\cos R \geq \left(\frac{q-r}{p+q}\right) cos P + \left(\frac{p-r}{q+p}\right) \cos Q$$
$$\frac{q+r}{p} < 2 \frac{\sqrt{\sin Q \sin R}}{\sin P}$$
If p < q and p < r, then $$\cos Q > \frac{p}{r}$$ and $$\cos R >\frac{p}{q}$$
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