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ABC is an equilateral triangle. $$AB=10\text{cm}$$. D is a point outside $$\triangle ABC$$ such that $$BD=DC$$ and $$\angle BDC = 120^\circ$$. Points M, N are on sides AB and AC respectively such that $$\angle MDN = 60^\circ$$. Find the perimeter of $$\triangle AMN$$.
Correct Answer: 20
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