A function $$y = f(x)$$ has a second order derivative $$f''(x) = 6(x - 1)$$. If its graph passes through the point $$(2, 1)$$ and at that point the tangent to the graph is $$y = 3x - 5$$, then the function is

A

$$(x - 1)^2$$

B

$$(x - 1)^3$$

C

$$(x + 1)^3$$

D

$$(x + 1)^2$$