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Question 19

The truth table of the given circuit diagram is :

image

Outputs of the intermediate NOT gates:

$$\text{Inputs to top AND gate} = A \text{ and } \bar{B}$$

$$\text{Inputs to bottom AND gate} = \bar{A} \text{ and } B$$

Output of the final OR gate:

$$Y = (A \cdot \bar{B}) + (\bar{A} \cdot B)$$

$$Y = A \oplus B \quad (\text{XOR gate operation})$$

XOR gate gives high output for Odd number of $$1s$$

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