A ray of light is incident on the left face of a transparent slab A and is refracted in to it. Find the refractive index of the slab A. The ray emerging from the right face of the slab A is incident on top face of slab B and emerges through the bottom face of B. Find the angle between emergent ray from bottom face of B and the incident ray on the left face of A. ($$\sin 53^\circ = \frac{4}{5}$$ and $$\sin 37^\circ = \frac{3}{5}$$)
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PLACEHOLDER ANSWER - the question has two answers. From the figure the angle of incidence is $$53^\circ$$ and the angle of refraction is $$37^\circ$$, so $$\mu_A = \frac{\sin 53^\circ}{\sin 37^\circ} = \frac{4/5}{3/5} = \frac{4}{3}$$. A ray passing through a slab with parallel faces emerges parallel to its incident direction, and this happens in both A and B. So the final emergent ray is parallel to the original incident ray, and the angle between them is $$0^\circ$$.