Question 183

If the fractions $$\frac{4}{9}, \frac{7}{12}, \frac{3}{7}, \frac{12}{17}$$ and $$\frac{1}{2}$$ are arranged in descending order of their values. which one will be the third

Solution

$$\frac{4}{9}=0.444$$

$$\frac{7}{12}=0.583$$

$$\frac{3}{7}=0.429$$

$$\frac{12}{17}=0.706$$

$$\frac{1}{2}=0.500$$

Since,

$$0.706>0.583>0.500>0.444>0.429$$

Therefore,

$$\frac{12}{17}$$>$$\frac{7}{12}$$>$$\frac{1}{2}$$>$$\frac{4}{9}$$>$$\frac{3}{7}$$

So, When arranged in descending order third term is $$\frac{1}{2}$$.

Hence, Correct Option is D.

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