Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
Narrow square paths ABCD and abcd have sides of $$200\text{ m}$$ and $$100\text{ m}$$. Two persons P and Q are initially located at a and A respectively. They both start walking in a clockwise sense.<br>Starting from the same initial positions P and Q walk at $$1\text{ m/s}$$ and $$2\text{ m/s}$$ respectively, find the shortest distance (in m) between them.
[image]
Correct Answer: 50
The two paths are concentric squares whose parallel sides are $$50\text{ m}$$ apart, so P and Q can never be closer than 50 m. At $$t = 50\text{ s}$$, P has walked 50 m from a to the middle of side ab and Q has walked 100 m from A to the middle of side AB, directly opposite. So the shortest distance is 50 m.
Was this solution helpful?
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.