Instructions

Consider the functions defined implicitly by the equation $$y^2 - 3y + x = 0$$ on various intervals in the real line. If $$x \in (-\infty, -2) \bigcup (2, \infty)$$, the equation implicitly defines a unique real valued differentiable function y = f(x). If $$x \in (-2, 2)$$, the equation implicitly defines a unique real valued differentiable function y = g(x) satisfying g(0) = 0.

Question 18

If $$f(-10\sqrt{2}) = 2\sqrt{2}$$, then $$f''(-10\sqrt{2}) =$$

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JEE (Advanced) 2008 Paper-1

If $$f(-10\sqrt{2}) = 2\sqrt{2}$$, then $$f''(-10\sqrt{2}) =$$

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