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For an experiment in the laboratory only two solutions are available.
Solution A - 250 g of 40% (w/w) NaCl solution and
Solution B - 300 g of 60% (w/w) NaCl solution
The Maximum weight of a solution (having exactly 55% (w/w) NaCl concentration) that can be prepared by the mixing of Solution A and Solution B only can be
Mixing x g of A with y g of B gives 55% when $$0.4x + 0.6y = 0.55(x + y)$$, i.e. $$0.05y = 0.15x$$ or $$y = 3x$$. Since only 300 g of B is available, the most we can use is $$y = 300$$ g with $$x = 100$$ g of A. The maximum mass of the 55% solution is $$100 + 300 = 400$$ g.
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