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A circle $$C$$ of radius 2 lies in the second quadrant and touches both the coordinate axes. Let $$ r$$ be the radius of a circle that has centre at the point (2, 5) and intersects the circle $$ C $$ at exactly two points. If the set of all possible values of r is the interval $$(\alpha, \beta), \text{ then } 3\beta - 2\alpha \text{ is equal to :} $$
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