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Question 179

If in a frequently distribution, the mean and median are $$21$$ and $$22$$ respectively, then its mode is approximately

Solution

For a moderately skewed, unimodal frequency distribution, Karl Pearson’s empirical relation between mean, median and mode is used:

$$\text{Mode} \approx 3(\text{Median}) - 2(\text{Mean})$$

Given values:
Mean $$= 21$$,  Median $$= 22$$

Substituting in the formula:

$$\text{Mode} \approx 3 \times 22 \;-\; 2 \times 21$$

$$\text{Mode} \approx 66 \;-\; 42 = 24$$

Therefore, the mode of the distribution is approximately $$24.0$$.

Option D which is: $$24.0$$

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