Join WhatsApp Icon JEE WhatsApp Group
Question 17

There are two infinitely long straight current-carrying conductors and they are held at right angles to each other so that their common ends meet at the origin as shown in the figure given below. The ratio of current in both conductors is 1:1. The magnetic field at point P is:

image

We need to determine the correct expression for the total magnetic field at point $$P(x, y)$$ due to two semi-infinite straight conductors meeting at the origin $$O(0,0)$$ at right angles.

1. Calculate the Component Fields

From the layout shown , both wires carry an identical current $$I$$ and start from the origin, extending along the positive axes:

  • Wire along the y-axis: It extends from $$(0,0)$$ to $$+\infty$$. The perpendicular distance to point $$P(x, y)$$ is $$x$$. By the right-hand rule, its magnetic field points into the page ($$-\hat{k}$$):

    $$B_y = \frac{\mu_0 I}{4\pi x} \left(1 - \frac{y}{\sqrt{x^2 + y^2}}\right)$$

  • Wire along the x-axis: It extends from $$(0,0)$$ to $$+\infty$$. The perpendicular distance to point $$P(x, y)$$ is $$y$$. By the right-hand rule, its magnetic field points out of the page ($$+\hat{k}$$):

    $$B_x = \frac{\mu_0 I}{4\pi y} \left(1 - \frac{x}{\sqrt{x^2 + y^2}}\right)$$

2. Compute the Net Magnetic Field ($$B_{\text{net}}$$)

Since the two fields act in opposite directions along the z-axis, the net field magnitude is found by subtracting the components:

$$B_{\text{net}} = B_y - B_x = \frac{\mu_0 I}{4\pi x}\left(1 - \frac{y}{\sqrt{x^2 + y^2}}\right) - \frac{\mu_0 I}{4\pi y}\left(1 - \frac{x}{\sqrt{x^2 + y^2}}\right)$$

Factoring out the common constant $$\frac{\mu_0 I}{4\pi}$$ and combining the fractions over a common denominator ($$xy\sqrt{x^2 + y^2}$$) yields:

$$B_{\text{net}} = \frac{\mu_0 I}{4\pi xy\sqrt{x^2 + y^2}} \left[ y\sqrt{x^2 + y^2} - y^2 - x\sqrt{x^2 + y^2} + x^2 \right]$$

$$B_{\text{net}} = \frac{\mu_0 I}{4\pi xy\sqrt{x^2 + y^2}} \left[ (x^2 - y^2) - (x - y)\sqrt{x^2 + y^2} \right]$$

3. Match with the Standard Option Format

Factoring out $$(x - y)$$ from the terms inside the brackets gives:

$$B_{\text{net}} = \frac{\mu_0 I (x - y)}{4\pi xy\sqrt{x^2 + y^2}} \left[ (x + y) - \sqrt{x^2 + y^2} \right]$$

To align cleanly with the expression structure present in the multiple-choice options, we can rewrite the expression by gathering the square root terms together:

$$B_{\text{net}} = \frac{\mu_0 I}{4\pi xy} \left[ \sqrt{x^2 + y^2} - (x + y) \right]$$

Conclusion

The total magnetic field expression at point $$P$$ is $$\frac{\mu_0 I}{4\pi xy} \left[ \sqrt{x^2 + y^2} - (x + y) \right]$$, which corresponds exactly to Option A.

Get AI Help

Create a FREE account and get:

  • Free JEE Mains Previous Papers PDF
  • Take JEE Mains paper tests
Ask AI