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The piston is now pulled out slowly and held at a distance 2L from the top. The pressure in the cylinder between its top and the piston will then be
$$P_0$$
$$\frac{P_0}{2}$$
$$\frac{P_0}{2} + \frac{Mg}{\pi R^2}$$
$$\frac{P_0}{2} - \frac{Mg}{\pi R^2}$$
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