Question 17

The least number of square tiles required to pave the floor of a room 15 m 91 cm and 9 m 46 cm broad is

Solution

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Let the number of square tiles be n and the area of each square tile be $$x^2$$

Length = 1591 cm

Breadth = 946 cm

x is the H.C.F of 1591 and 946.

$$1591$$ = $$43\times37$$

$$946$$ = $$43\times2\times11$$

x = 43

Hence, all the dimensions can be covered in squares of dimensions 43 cm.

n(43)(43) = (1591)(946)

n = 37*22 = 814

The answer is option A.

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