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An $$\alpha$$ particle, a proton and an electron have the same kinetic energy. Which one of the following is correct in case of their de-Broglie wavelength:
$$\lambda = \frac{h}{p} = \frac{h}{\sqrt{2mK}}$$
$$\lambda \propto \frac{1}{\sqrt{m}}$$
$$m_e < m_p < m_\alpha$$
$$\lambda_e > \lambda_p > \lambda_\alpha$$
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