A parallel plate capacitor of area 60 cm$$^2$$ and separation 3 mm is charged initially to 90$$\mu$$C. If the medium between the plate gets slightly conducting and the plate loses the charge initially at the rate of $$2.5 \times 10^{-8}$$ C/s, then what is the magnetic field between the plates?

The magnetic field is determined by the Maxwell-Ampere law, which accounts for both conduction and displacement currents. Inside a conductor, charges flow on the surface, and there is no net current flowing through the interior volume. Since the leaking capacitor acts as a conductor, the internal current is effectively zero. Consequently, applying Ampere’s law with these conditions confirms that the magnetic field inside the capacitor is zero.