A man walked 9 km towards East and then 12 km towards South. How far is he from the starting point?
Let the man started from point A and finally reached point C.
Thus, in right angled $$\triangle$$ ABC, => $$(AC)^2=(AB)^2+(BC)^2$$
=>Â $$(AC)^2=(9)^2+(12)^2$$
=> $$(AC)^2=81+144=225$$
=> $$AC=\sqrt{225}=15$$ km
=> Ans - (C)
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