(A) : The sum of all internal angles in a pentagon is 540°
(R) : A pentagon has 5 sides

Solution

Sum of all internal of a polygon is

$$(n-2)180°.$$

Condition R:

we know that a pentagon has 5 sides.

So, Condition A:

Sum of all internal angles of a pentagon is

$$(5-2)×180°=3×180°=540°.$$

So, both the conditions are correct and A is dependent on R.

So, Option A is correct choice.

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(A) : The sum of all internal angles in a pentagon is 540°(R) : A pentagon has 5 sides