The kinetic energy of an electron, $$\alpha$$-particle and a proton are given as 4K, 2K and K respectively. The de-Broglie wavelength associated with electron $$(\lambda_e)$$, $$\alpha$$-particle $$(\lambda_\alpha)$$ and the proton $$(\lambda_p)$$ are as follows:

A

$$\lambda_\alpha = \lambda_p > \lambda_e$$

B

$$\lambda_\alpha < \lambda_p < \lambda_e$$

C

$$\lambda_\alpha = \lambda_p < \lambda_e$$

D

$$\lambda_\alpha > \lambda_p > \lambda_e$$