Question 16

In triangle $$ABC$$, right angled at $$A$$, $$AD$$ is the altitude on to the side $$BC$$. If $$AD = 6$$ and $$BD = 9$$ then $$CD =$$

Solution

In a right triangle the altitude to the hypotenuse satisfies $$AD^2 = BD \cdot CD$$, since $$\triangle ABD \sim \triangle CAD$$. So $$36 = 9 \times CD$$ and $$CD = 4$$.

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