David gets on the elevator at the 11th floor of a building and rides up at the rate of 57 floors per minute. At the same time Albert gets on an elevator at the 51st floor of the same building and rides down at the rate of 63 floors per minute. If they continue traveling at these rates, then at which floor will their elevators meet?
Solution
Let them meet at time "t"
Floor of David at time t = 11+57t
Floor of Albert at time t = 51- 63t
When they meet their floor will be same. 11+57t = 51 - 63t
t = $$\dfrac{1}{3}$$ minutes.
Floor at which they meet = 11 + 57 *$$\dfrac{1}{3}$$ = 11+19 = 30
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