Question 150

If the area of a square is increased by 44%, retaining its shape as a square, each of its sides increases by:

Solution

Let the side of square be $$a=10$$ cm

=> Area = $$A=10\times10=100$$ $$cm^2$$

New area = $$100+(\frac{44}{100}\times100)=144$$ $$cm^2$$

=> New side = $$a'=\sqrt{144}=12$$ cm

$$\therefore$$ Increase in area = $$\frac{(12-10)}{10}\times100$$

= $$2\times10=20\%$$

=> Ans - (D)

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