Question 150
If the area of a square is increased by 44%, retaining its shape as a square, each of its sides increases by:
Solution
Let the side of square be $$a=10$$ cm
=> Area = $$A=10\times10=100$$ $$cm^2$$
New area = $$100+(\frac{44}{100}\times100)=144$$ $$cm^2$$
=> New side = $$a'=\sqrt{144}=12$$ cm
$$\therefore$$ Increase in area = $$\frac{(12-10)}{10}\times100$$
= $$2\times10=20\%$$
=> Ans - (D)
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