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Question 150
If 6, 5, 4 and 3 occur in a data with frequencies 2, 5, 3 and 4 respectively, then the arithmetic mean of the data is
Solution
Arithmtic Mean = $$\frac{\Sigma\ \left(\ distinct\ values\ \times\ frequency\right)}{\Sigma\ \left(frequency\right)}\ $$
= $$\frac{6\ \times\ 2\ \ +\ 5\times\ 5\ +\ 4\times\ 3\ +\ 3\times\ 4}{2+5+3+4}\ $$
= $$\frac{61}{14}$$ Answer
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