The figure shows a capacitor of capacitance C connected to a battery via a switch, having a total charge Q on it, in steady-state. When the switch S is turned from position A to position B, the energy dissipated in the circuit is

A

$$\frac{1}{8}\frac{Q^2}{C}$$

B

$$\frac{3}{8}\frac{Q^2}{C}$$

C

$$\frac{3}{4}\frac{Q^2}{C}$$

D

$$\frac{5}{8}\frac{Q^2}{C}$$