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If the diagonals of a rhombus are $$8\ \text{cm}$$ and $$6\ \text{cm}$$, then perimeter of the rhombus is
The diagonals of a rhombus bisect each other at right angles, so each side is the hypotenuse of a right triangle with legs 4 cm and 3 cm. The side is $$\sqrt{4^2 + 3^2} = 5\ \text{cm}$$. The perimeter is $$4 \times 5 = 20\ \text{cm}$$.
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