Question 15
An object with a mass of 22 kg moving with a velocity of 5 m/s possesses a kinetic energy of:
Solution
We know that,
K.E. = $$\frac{1}{2}mv^2$$
We have
$$M=22 kg$$
$$V=5ms^{-1}$$
K.E. = $$\frac{1}{2}mv^2$$
=$$\frac{1}{2}\times22\times5^{2}$$
= 275 J
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