Question 15

An object with a mass of 22 kg moving with a velocity of 5 m/s possesses a kinetic energy of:

Solution

We know that,

K.E. = $$\frac{1}{2}mv^2$$

We have

$$M=22 kg$$

$$V=5ms^{-1}$$

K.E. = $$\frac{1}{2}mv^2$$

=$$\frac{1}{2}\times22\times5^{2}$$

= 275 J

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