Solution
When two dice are thrown, the possible cases of getting a sum of 9 are (3,6) (4,5) (5,4) (6,3)
Number of favourable cases = 4
Total possibilities = 6 x 6 = 36
$$\therefore\ $$Required probability = $$\frac{4}{36}$$ = $$\frac{1}{9}$$
Hence, the correct answer is Option C
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